We know that the scale is `1/5` .

Write the scale as a unit rate.

`(1/5) = (12/x)`

where `x ` is the unknown actual distance for `12` inches.

Multiply both sides by` 5x` .

`(5x)(1)/(5) = (12/x)*(5x)`

`(5x)/(5) = (12*5x)/(x)`

Cancel out common factor on top and bottom.

`1x...

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We know that the scale is `1/5` .

Write the scale as a unit rate.

`(1/5) = (12/x)`

where `x ` is the unknown actual distance for `12` inches.

Multiply both sides by` 5x` .

`(5x)(1)/(5) = (12/x)*(5x)`

`(5x)/(5) = (12*5x)/(x)`

Cancel out common factor on top and bottom.

`1x = 60`

Isolate the x on left side, divide both side by 1.

`x = 60`

Therefore, **the actual distance for 12 inches is 60 miles**.

That is it!